funny title goes here
2y 2mon ago by mander.xyz/u/fossilesque in science_memes@mander.xyz from mander.xyz
Can someone explain this to me? Not the maths, the joke.
Hrm, it sounds like the teacher already knew the answer.
Maybe stop wasting the time of the student then!?
You're welcome.
The test:
Solve e{int_0 1 x2+x+1 dx}
No, copilot solve this test
Answer:
To solve the expression ( e{\int_01 x2+x+1 , dx} ), we first need to calculate the integral of ( x2+x+1 ) from 0 to 1.
The integral of ( x2+x+1 ) is: [ \int x2+x+1 , dx = \frac{x3}{3} + \frac{x2}{2} + x + C ]
Evaluating this from 0 to 1 gives us: [ \left[ \frac{x3}{3} + \frac{x2}{2} + x \right]_0^1 = \left( \frac{1}{3} + \frac{1}{2} + 1 \right) - \left( 0 + 0 + 0 \right) = \frac{11}{6} ]
Now, we raise ( e ) to the power of this result: [ e^{\frac{11}{6}} ]
This is the solution to the given expression. If you need a numerical approximation, ( e^{\frac{11}{6}} ) is approximately 4.953.
...and this student was Albert Einstein